f(x) = 3x/x+1 dan g(x) = x/2x+2 . jika h(x) = (f+g)(x), invers fungsi h adalah?

Fungsi H(x) = 7x / 2x + 2
f(x) = (ax + b)/(cx+d) ---> f^-1(x) = (-dx + b)/(cx – a)
Jadi H^-1(x) = -2x/(2x-7)

[tex]h(x) = (f+g)(x) = f(x)+g(x) = \frac{3x}{(x+1)} + \frac{x}{(2x+2)} = \frac{2.3x}{2(x+1)}+ \frac{x}{(2x+2)} \\ h(x) = \frac{6x}{(2x+2)} + \frac{x}{(2x+2)} \\ h(x)= \frac{7x}{(2x+2)} [/tex]
fungsi [tex]h(x) = \frac{(ax+b)}{(cx+d)} [/tex] inversnya adalah [tex] h^{-1} (x) = \frac{(-dx+b)}{(cx -a)} [/tex]jadi [tex]h x^{-1}(x) = \frac{-2x}{2x-7} [/tex]