Berapakah panjang bd?

panjang AE = 4
panjang EC = 20
panjang CD = 17
panjang AC = AE + EC = 4 + 20 = 24
panjang BD = ?
ketentuan rumus phytagoras
3 : 4 : 5
segitiga CAB
3 : 4 : 5 = AB : AC : BC = AB : 24 : BC
AB -> 3 x 6 = 18
AC -> 4 x 6 = 24
BC -> 5 x 6 = 30
BC = CD + BD
30 = 17 + BD
BD = 30 - 17
BD = 13