Diketahui x0 dan y0 memenuhi sistempersamaan linear 2x+9y=21 dan 4x -5y =19 nilai 1/3 x0 -3y0=

Pers. 1
2x + 9y = 21 ( dikali 2 )
Pers. 2
4x - 5y = 19 ( dikali 1 )

Eliminasi persamaan 1 dan 2
4x + 18y = 42
4x - 5y = 19
------------------- - (dikurangin)
23y = 23
y = 23/23
y = 1 >>> Yo = 1

Subtitusi dari persamaan 2
4x - 5y = 19
4x - 5(1) = 19
4x - 5 = 19
4x = 19 + 5
4x = 24
x = 24/4
x = 6 >>> Xo = 6

[tex] \frac{1}{3} xo - 3yo \\ ( \frac{1}{3} \times 6) -( 3 \times 1 ) \\ = 2 - 3 \\ = - 1[/tex]

semoga membantu ^^