Tolong bantu sayaa bsk saya ujiaannn

[tex]no \: 4 \\ \frac{4}{\sqrt{7} - \sqrt{3} } \\ = \frac{4}{ \sqrt{7} - \sqrt{3} } \times \frac{ \sqrt{7} + \sqrt{3} }{ \sqrt{7} + \sqrt{3} } \\ = \frac{4( \sqrt{7} + \sqrt{3}) }{7 - 3} \\ = \frac{4( \sqrt{7} + \sqrt{3}) }{4} \\ = \sqrt{7} + \sqrt{3} [/tex]
[tex]no \: 5 \\ {5}^{x + 3} = {25}^{3x - 4} \\ {5}^{x + 3} = {5}^{2(3x - 4)} \\ x + 3 = 2(3x - 4) \\ x + 3 = 6x - 8 \\ x - 6x = - 8 - 3 \\ - 5x = - 11 \\ x = \frac{ - 11}{ - 5} = \frac{11}{5} = 2 \frac{1}{5} [/tex]
maaf cuma segitu