tolong dijawab dengan cara

<BCA = 180 - 108 = 72°
<BAC = 180 - 72 -36 = 72° (C)
maaf kalau salah

→ Mapel : Math
→ Materi : Sudut
→ Bab : Aljabar
————————————————

Besar ACB
= 180° - 108°
= 72°

Besar BAC
= 180° - ( 72° + 36° )
= 180° - 108°
= 72°
Opsi → C[tex] [/tex]

Happy Learn :)