Jika x1 dan x2 akar persamaan kuadrat x² - (5-a) x - 5 = 0 dan x1 - x2 = 2√6 maka nilai a adalah... tolong di bantu ya kk bg...

[tex] {x}^{2} - (5 - a)x - 5 = 0 \\ x1 - x2 = 2 \sqrt{6} \: \: \: \: x2 = x1 - 2 \sqrt{6} \\ x1.x2 = x1(x1 - 2 \sqrt{6} ) = {x1}^{2} - 2x1 \sqrt{6} = - 5 \\ {x1}^{2} - 2x1 \sqrt{6} + 5 = 0\\ {(x1 - \sqrt{6} )}^{2} - 6 + 5 = 0 \\ (x1 - \sqrt{6}) = \sqrt{1} = 1 \\ x1 = \sqrt{6} + 1\\x2 = 1 - \sqrt{6} \\ x1 + x2 = (5 - a) \\x1 + x2 = 2 = 5 - a \\ a = 3[/tex]