pake cara yg jelas ya

Pers. garis l yg melalui titik (4,0) & (0,6)
[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ \frac{y - 0}{6 - 0} = \frac{x - 4}{0 - 4} \\ \frac{y}{6} = \frac{x - 4}{ - 4} \\ - 4y = 6x - 24 \\ - 2y = 3x - 12[/tex]
m1 = 3/-2

Syarat tegak lurus yaitu m1 × m2 = -1
3/-2 × m2 = -1
m2 = -1 : 3/-2
m2 = -1 × -2/3
m2 = 2/3

Pers. garis k yg melalui titik (0,2) & gradien = 2/3
y - y1 = m (x - x2)
y - 2 = 2/3 (x - 0)
y - 2 = 2/3x
-2/3x + y - 2 = 0 (*semua ruas dikali -3)
2x - 3y + 6 = 0

Jawabannya A.