Diketahui segitiga ABC dengan panjang sisi dan sudut : a. 12.5cm; b. 10cm;

[tex] \frac{a}{ \sin(A) } = \frac{b}{ \sin(B) } \\ \frac{a}{b} = \frac{ \sin(A) }{ \sin(B) } \\ \frac{12.5}{10} = \frac{ \sin(110) }{ \sin(B) } \\ \frac{0.94}{ \sin(B) } = 1.25 \\ \sin(B) = \frac{0.94}{1.25} \\ \sin(B) = 0.752 \\ B = 49 [/tex]
B= 49°

A+B+C = 180°
C = 180-(110° + 49°) = 21°

[tex] \frac{c}{ \sin(C) } = \frac{a}{ \sin(A) } \\ \frac{c}{a} = \frac{ \sin(C) }{ \sin(A) } \\ \frac{c}{12.5} = \frac{ \sin(21) }{ \sin(110 ) } \\ c = \frac{0.36}{0.94} \times 12.5 \\ c = 4.79 \: cm[/tex]

#semoga membantu :)