pd peristiwa melempar 2bh dadu merah dn hitam,masing² bermata1 sampai 6 scara bersamaan sebanyak 1 kali.berapakah nilai peluang kejadian².(a)muncul 4dadu merah/

a.)) 4 merah atau ganjil hitam
a= 4merah
n(a)=1

p(a) =n(a)/n(s)
= 1/6

b= ganjil hitam = 1,3,5
n(b)=3

p(b) =n(b)/n(s)
= 3/6
= 1/2

p(a u b) = p(a) + p(b)
= 1/6 + ½
= 1/6 + 3/6
= 4/6
= 2/3

b.)) merah < 3dan hitam >4
a= merah <3 = 1,2
n(a)=2

p(a) =n(a)/n(s)
= 2/6
= ⅓

b= hitam >4 = 5,6
n(b)=2

p(b) =n(b)/n(s)
= 2/6
= ⅓

p(a n b) = p(a).p(b)
= ⅓ . ⅓
= 1/9

semoga mmbantu