1. f (x) = x²-6, g(x)= √x+1, hitung (fog) (3) dan (gof) (1) 2. f (x)= x²+2x-1, g(x)= 2x+1, h(x) = 1/2 hitunglah [(fog)oh] (3) dan [fo(goh)] (3)

1. f(x) = x²- 6 , g(x)= √x+1
g(3) = √3+1 , f(1) = x²- 6 -> 1 - 6 = -5
(fog)(3) = (√3+1)²- 6
= (√3+1)(√3+1) - 6
= 3+√3+√3+1 - 6
= 2√3+4-6 -> 2√3-2
(gof)(1) = √x+1 = √-5 + 1

2.