Yang no 6 sama no 7 ya

No.6 (Sudut Pusat dan Sudut Keliling)
<AOB = 2 x <BCA
<AOB = 2 x 30°
<AOB = 60°

<ABO = (180° - 60°) : 2
<ABO = 120° : 2
<ABO = 60°

<ABC = <ABO + <CBO
<ABC = 60° + 15°
<ABC = 75°

No.7 (Lingkaran)
K juring besar = <AOB/360° x K lingkaran
= 45°/360° x 2 x π x r
= 1/8 x 2 x 3,14 x (6+5)
= 1/4 x 3,14 x 11
= 8,635 cm

K juring kecil = <AOB/360° x K lingkaran
= 45°/360° x 2 x π x r
= 1/8 x 2 x 3,14 x 6
= 1/4 x 3,14 x 6
= 4,71 cm

K arsiran = 8,635 + 4,71 + 2 x 5
= 13,345 + 10
= 23,345 cm

*semoga membantu. sukses selalu ^_^

Mapel Matematika
Bab Lingkaran

6.
Mencari sudut pusat AOB dari sudut keliling BCA
AOB = 2 x BCA
AOB = 2 x 30°
AOB = 60°

Mencari sudut ABO
ABO = (180° - AOB) / 2
ABO = (180° - 60°) / 2
ABO = 120° / 2
ABO = 60°

Mencari sudut ABC
ABC = ABO + CBO
ABC = 60° + 15°
ABC = 75°


7.
Keliling juring besar
= AOB/360° x K
= 45°/360° x (2πr)
= 1/8 x (2 x 3,14 x (6+5))
= 8,635 cm

Keliling juring kecil
= AOB/360° x K
= 45°/360° x (2πr)
= 1/8 x (2 x 3,14 x 6)
= 4,71 cm

Keliling arsiran
= Kjuring besar + Kjuring kecil + Sisi samping
= 8,635 + 4,71 + 2(5)
= 13,345 + 10
= 23,345 cm