Matematika

Pertanyaan

aku minta tolong banget buat temen2 yang bisa, soalnya aku ga tau lagi mau cari dimana dan aku nggak ngerti juga. tolong banget ya temen2 senin mau dikumpul, ilmunya dibagi bagi biar berkah. aku kasih poin 30 deh, tapi jangan ngasal yah , kalo ngasal nanti aku block.
aku minta tolong banget buat temen2 yang bisa, soalnya aku ga tau lagi mau cari dimana dan aku nggak ngerti juga. tolong banget ya temen2 senin mau dikumpul, il

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1 Jawaban

  • 1. f(u) = u + 4 / u - 6 , g(u) = 2u - 1
    (fog)^-1 (u)
    (fog)^-1 = 1/(fog)(u)
    (fog)(u) = (2u - 1) + 4 / (2u - 1) - 6
    = 2u + 3 / 2u - 7
    (fog)^-1 = 1/((2u + 3)/(2u - 7))
    = 2u - 7 / 2u + 3

    2. f(u) = 3u + 2 , f(g(u)) = -12u + 23
    g(u) = -4u + 7
    -4 = -12/3
    7 = (23-2)/3 = 21/3

    3. f(u) = 3/u , g(u) = u - 4
    (fog)(u) = (gof)(u)
    u = ?
    (fog)(u) = (gof)(u)
    3/u-4 = (3/u) - 4
    3/u-4 = (3/u) - (4/1)
    3/u-4 = (3/u) - (4u/u)
    3/u-4 = (3-4u)/u
    3u = (3-4u)(u-4)
    3u = 3u-12-4u^2+16u
    0 = 3u-12-4u^2+16u-3u
    0 = -4u^2+16u-12
    0 = 4u^2-16u+12
    disederhanakan lagi
    0 = u^2-4u+3
    0 = (u-1)(u-3)
    u = 1 dan u = 3

    5. g(u) = u^2+2u+3
    (fog)(u) = 3u^2+6u+5
    f(u) = ?
    f(u-1) = ?

    6. f(u) = 3 - 3u , g(u) = 2u
    (gof)^-1(5) = ?
    (gof)^-1 = 1/gof(5)
    (gof)(x) = 2(3-3u) = 6-6u
    (gof)(5) = 6-6(5) = 6 -30 = - 24
    (gof)^-1 = 1/gof(5) = 1/-24

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