tolong jawab berserta caranya ya tentukan persamaan garis yang melalui titik A(3,5) & B(7,11)

y-y1/ y2-y1 = x-x1/x2-x1
y-5/11-5 = x-3/7-3
y-5 / 6 = x-3 / 4
4 (y-5) = 6 ( x-3 )
4y - 20 = 6x - 18
4y = 6x - 18 + 20
4y = 6x - 2
(4y = 6X - 2 ) : 2
2y = 3x - 1
(2y = 3x - 1 ) : 2
y = 3/2 x - 1/2

Y-y1/y2-y1 = x-x1/x2-x1 jadi y-5/11-5 = x-3/7-3 Y-5/6 = x-3/4 6(x-3) = 4(y-5) 6x-18 =4y-20 6x-4y-18+20=0 6x-4y+2 =0 Atau jika diperkecil menjadi 3x-2y+1=0