Jika 5log 3 =p dan 5log 7 = , maja nilai nilai dari 45log 175√3

^5log7 dianggap= q
^45log175√3 ubah pd basis 5
= ^5log175√3/^5log45
= ^5log(5^2.7.3^(1/2))/^5log(3^2.5)
= (2.^5log5 + ^5log7 + (1/2).^5log3)/(2.^5log3 + ^5log5)
= (2 + q + p/2)/(2p + 1)
=((4 + 2q + p)/2) / (2p + 1)
= (p + 2q + 4)/[2(2p + 1)]