nilai dari ²log 0,25 + 5log 100+5 log 5-5 log 4-7 log 49

Kelas 10 Matematika
Bab Logaritma

²log 0,25 + ⁵log 100 + ⁵log 5 - ⁵log 4 - ⁷log 49
= ²log (1/4) + ⁵log 100 - ⁵log 4 + ⁵log 5 - ⁷log 49
= ²log 2⁻² + ⁵log (100 : 4) + 1 - ⁷log 7²
= -2 + ⁵log 25 + 1 - 2
= -2 + ⁵log 5² + 1 - 2
= -2 + 2 + 1 - 2
= -1