hitunglah PH larutan 100 ml KNO3 0,001 M

Mapel: Kimia
Kelas: XI
Materi: Asam Basa

Jawab

KNO3 → K+ + NO3-

[H+] = M×Va
[H+] = 0.001×1
[H+] = 10-³

pH= -log[H+]
pH= -log 10-³
pH = 3