Matematika

Pertanyaan

2log5=p 3log3=q nilai 13log20

1 Jawaban

  • ²log5 = p
    ³log5 = q

    15log20 = ²log20/²log15
    = ²log(4x5)/²log(3x5)
    = (²log2² + ²log5)/(²log3 + ²log5)
    = (2 + p)/(p/q + p)
    = (2+p)/(pq+p)/q
    = q(2+p)/(pq+p)
    = (2q + PQ)/(PQ + p)

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