3 log 4=p dan 3 log 5=q. nilai dari 6 log 240=
Matematika
matroji8600
Pertanyaan
3 log 4=p dan 3 log 5=q. nilai dari 6 log 240=
1 Jawaban
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1. Jawaban Anonyme
^3log4 = ^3log2^2 = 2.^3log2 = p
^3log2 = p/2 dan ^3log5 = q
^6log240 = ^3log240/^3log6
= ^3log(2^4.3.5)/^3log(2.3)
= (4.^3log2 + ^3log3 + ^3log5)/(^3log2 + ^3log3)
= (4(p/2) + 1 + q)/(p/2 + 1)
= (2p + 1 + q)/((p + 2)/2)
= 2(2p + 1 + q)/(p + 2)