Suatu fungsi di rumuskan f(×)=a×+b jika f(-2)=14 dan f(3)=-1 maka nilai dari f(0) adalah...

f(-2)=-2a+b=14
f (3)= 3a+b=-1
----------------------   -
          -5a=15
              a=-3
          b=3.-3+b=-1 -9+b=-1b=8
f(0)=2.0+b=0+8=8

semoga membantu :)

◾ Materi : Fungsi
◾ Sub materi : Fungsi
◾ Mapel : Matematika
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Jawab :
f(x) = ax+b

f(-2) = 14
a(-2) + b = 14
-2a + b = 14
b = 14 + 2a..... (1)

f(3) = -1
a(3) + b = -1
3a + (14 + 2a) = -1
3a + 2a + 14 = -1
5a = -1 - 14
5a = -15
a = -15/5
a = -3

b = 14 + 2a
b = 14 + 2(-3)
b = 14 - 6
b = 8

Maka, f(x) = ax + b
f(x) = -3x + 8

f(0) = -3(0) + 8
f(0) = 0 + 8
f(0) = 8

semoga membantu
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-vin