tolong bantu lagi Yah dengan cara penyelesaian pelajaran Mtk peminatan kelas 10

9.
a tegak lurus c
2. 11+ (-2)p+ 1q = 0
-2p+q = - 22
q= -22+2p ...1)

b tegak lurus c
1.11 +3p+4q = 0
3p+ 4q = - 11 ...2)
substitusi 1 ke dalam 2
3p+4(-22+2p) = - 11
3p-88+8p = - 11
11p = -11+88
11p =77
p =77/11
p = 7

nilai q = -22+2.7=-22+14=-8

10.
PR: RQ = 3: 2
r =1/5( 3q + 2p) = 1/5 ( (30, -6,21)+(0,6,-6)
r= 1/5(30, 0, 15) = (6,0,3)

a = PR = r -p = (6,0,3) - (0,3,-3) =(6, -3, 6)
b = RQ = q -r = (10, -2,7) -(6,0,3) = (4, -2, 4)
ab = 6.4 +(3)(-2)+6.4= 24+(-6)+24=42