Matematika

Pertanyaan

fungsi g dinyatakan g (x)= qx+r nilai g(3)=-7 dan g(5)= 1 nilai g(9) adalah

2 Jawaban

  • Fungsi

    g(X) = qX + r
    g(3) = 3q + r = -7
    g(5) = 5q + r = 1

    3q + r = -7
    5q + r = 1
    _________ _
    -2q = -8
    q = -8/-2
    q = 4

    3q + r = -7
    3 x 4 + r = -7
    12 + r = -7
    r = -7 - 12
    r = -19

    g(9) = 9q + r
    g(9) = 9 x 4 + (-19)
    g(9) = 36 - 19
    g(9) = 17

    *semoga membantu. sukses selalu ^_^
  • g(x) = qx + r
    g(3) = q(3) + r = -7 ....... persamaan 1
    g(5) = q(5) + r = 1 ....... pers.2

    3q + r = -7
    5q + r = 1 (eliminasi)
    -> -2q = -8
    q = 4

    3q + r = -7
    3(4) + r = -7
    ->r = -7 - 12
    = -19

    Maka, g(9) = 4(9) + (-19) = 36-19 = 17

    Semoga membantu.. maaf kalo salah

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