Plissss jawab skrg kak

[tex] \cos(x) = - \frac{4}{5} \: \: \: \: \: \frac{1}{2} \pi \leqslant x \leqslant \pi \\ \sin(x) = \sqrt{1 - {cos}^{2}(x) } = \sqrt{1 - \frac{16}{25} } = \frac{3}{5} \\ \frac{ \csc(x) - \cos(x). \tan(x) }{ \cot(x) . \sec(x) } = \frac{ \frac{5}{3} - ( - \frac{4}{5})( - \frac{3}{4})}{ ( - \frac{4}{3} )( - \frac{5}{4} )} = \frac{ \frac{5}{3} - \frac{3}{5} }{ \frac{5}{3} } = \frac{ \frac{16}{15} }{ \frac{5}{3} } \\ = \frac{16}{15} \times \frac{3}{5} = \frac{16}{25} [/tex]