Matematika

Pertanyaan

2log6-2²log3+2log12=

1 Jawaban

  • 2log6= log6²
    2²log3=²log3² = log 9/2
    2log12=log12²

    log6² - log 9/2 +log12² 
    =log (36 ÷ 9/2) log12²
    =log (8 . 144)
    =log 1152

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