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Matematika
faisyah3
Pertanyaan
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1 Jawaban
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1. Jawaban agsa13
a. PR = SQ = 5cm
b. PS = RQ =
[tex] = \sqrt{ {20}^{2} + {52}^{2} } [/tex]
[tex] = \sqrt{400 + 2704} = \sqrt{3104} = 55.713[/tex]
PS = 55.713cm