Matematika

Pertanyaan

Nilai limit 2t^2-5t-25/125-t^3 dimana t menuju 5

2 Jawaban

  • limit 2t² - 5t -25/125-t³
    cara cepat diturunkan
    4t-5/3t²
    t(5) = 4.5-5 /3.5²
    =20-5 /3.25
    =15/75
    =1/5
  • [tex] \lim_{t \to 5} \frac{2t^2-5t-25}{125-t^3}= \lim_{t \to 5} \frac{(2t+5)(t-5)}{(5-t)(t^2+5t+25)} = \lim_{t \to 5} -\frac{(2t+5)(t-5)}{(t-5)(t^2+5t+25)}[/tex]
    [tex] \lim_{t \to 5} -\frac{(2t+5)}{(t^2+5t+25)}=- \frac{10+5}{25+25+25}= -\frac{15}{75} = -\frac{1}{5}[/tex]

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