Jika pertidaksamaan 3x - 4a > X 5/2- ax. maka mempunyai peyelesaian x > 2, maka nilai a terletak pada interval

[tex]3x-4a\ \textgreater \ \frac {5}{2}x-ax\\ 3x-\frac {5}{2}x+ax\ \textgreater \ 4a\\ x(3-\frac {5}{2}+a)\ \textgreater \ 4a\\ x(\frac {1}{2}+a)\ \textgreater \ 4a\\ x(\frac {2a+1}{2})\ \textgreater \ 4a\\ x\ \textgreater \ \frac {8a}{2a+1}.\\ x\ \textgreater \ 2\\2\ \textgreater \ \frac {8a}{2a+1}\\ 4a+2\ \textgreater \ 8a(jika\ a\ nya\ positif) \\ 4a\ \textless \ 2\\ a\ \textless \ \frac {1}{2}\\ \\ 4a+2\ \textless \ 8a(jika\ a\ nya\ negatif,\ tanda\ nya\ berubah)\\ 4a\ \textgreater \ 2\\ a\ \textgreater \ \frac {1}{2}\\ jadi\ a\ \textgreater \ \frac {1}{2} atau\ a\ \textless \ \frac {1}{2}\\ (maap\ kalo\ sala)[/tex]