Matematika

Pertanyaan

Integral 2 cos (1/3pi - 4x)

1 Jawaban

  • dianggap gini 2 cos((1/3)pi - 4x) dx
    u = (1/3)pi - 4x --> du = -4 dx
    dx = -(1/4) du
    = 2 int cos u (-1/4) du
    = -(1/2) int cosu du
    = -(1/2) sinu + c
    = -(1/2) sin(pi/3 - 4x) + c

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