tlg pakai jalan ny y no. 23 sm 24

no. 23:

diketahui
PQ = 15 cm (alas)
QU = 10 cm
L pqrs = 120 cm²

maka,

PQ . ST = PS . QU
15 . 8 = PS . 10
120 = 10PS
PS = 12 cm

*cara mencari ST (tinggi)*
L = a . t
120 = 15t
t = 8 cm

keliling PQRS
=2(a+b)
=2(PQ+PS)
=2(15+12)
=2(27)
=54 cm