koordinat titik balik minimum grafik y = x² + 4x - 5 adalah

Kelas 10 Matematika
Bab Fungsi Kuadrat

y = x² + 4x - 5
a = 1; b = 4; c = -5

Sumbu simetri
= -b/2a
= -4/(2 . 1)
= -2

y = (-2)² + 4 . (-2) - 5
y = 4 - 8 - 5
y = -9

(-2, -9)

f(x) = x^2 + 4x - 5
f'(x) = 2x + 4
f'(x) = 0
0 = 2x + 4
x = (-2)