turunan y= sin kuadrat (5x-phi)

[tex] {sin}^{2} (5x - \pi) = {( \sin(5x - \pi) )}^{2} \\ applying \: chain \: rule \\ \frac{dy}{dx} = 2 \sin(5x - \pi) \: . \: \cos(5x - \pi) \: . \: 5 \\ recall \: that \: \sin(2 \alpha ) = 2 \sin( \alpha ) \cos( \alpha ) \\ \sin(2(5x - \pi)) \: . \: 5 \\ = 5 \sin(10x - 2\pi) [/tex]