tolong di jawab beserta caranya

EF/AD = FG/CD
EF/21 = 15/20
EF = 15,75

tinggi trapesium kecil = 12, maka BG = 15,75+9 = 24,75

luas BGFE = (EF+BG)/2 x BE
= (15,75+24,75)/2 x 12
= 40,5 x 6 = 243 cm^2