POIN : 15 Pakai cara ya^^

[tex] \lim_{x \to \ 1} \frac{4 x^{4} -5 x^{3}+2 x^{2} -1 }{6 x^{3}-3 x^{2} -3 } = \lim_{x \to \ 1} \frac{(4 x^{3}- x^{2} +x+1)(x-1) }{(6 x^{2} +3x+3)(x-1)} [/tex]
coret (x - 1) kemudian ganti x dengan 1 diperoleh  [tex]= \frac{(4-1+1+1)}{(6+3+3)}= \frac{5}{12} [/tex]