tentukan turunan f(x)=(3x²+1)(x²+2x-5)

f(x) = (3x²+1)(x²+2x-5)
*gunakan sifat distributif
(3x²+1)(x²+2x-5)
=3x⁴+6x³-15x²+x²+2x-5
=3x⁴+6x³-14x²+2x-5

rumus turunan
[tex] {ax}^{n} = n. {ax}^{n - 1} [/tex]
*turunkan fungsinya
[tex] \frac{d}{dx} ( {3x}^{4} + {6x}^{3} - {14x}^{2} + 2x - 5 ) \\ = {12x}^{3} + 18x^{2} - 28x + 2[/tex]

(3X²×X²)+(3X²×2X)-(3X²×5)+(1×X²)+(1×2X)-(1×5)
=3X⁴+6X³-15X²+X²+2X-5
=3X⁴+6X³-14X²+2X-5
turunan
3X⁴+6X³-14X²+2X-5
=4×3X³+3×6X²-2×14X+2
=12X³+18X²-28X+2

semoga benar