fungsi rasional linear y=2x+1/x-3 melalui titik.....

[tex]f(-5)=\frac{-9}{-8}[/tex]
[tex]f(-2)=\frac{-3}{-5}[/tex]
[tex]f(0)=\frac{1}{-3}[/tex]
[tex]f(1)=\frac{3}{-2}[/tex]
[tex]f(2)=\frac{5}{-1}[/tex]
Titik yang dilalui [tex](-5,\frac{9}{8}),(-2,\frac{3}{5}),(0,-\frac{1}{3}),(1,-\frac{3}{2}),(2,-5) [/tex]