tanah pak mamad berbentuk persegi panjangdengan keliling 42 meter. jika panjang tanah (3x-2) meter dan lebar tanah (x+3) meter. maka luas tanah milik pak mama

Mapel : Matematika

K = 2 ( p + l )
42 = 2 ( ( 3x-2 ) + ( x + 3 ) )
42 = 2 ( 3x + x - 2 + 3 )
42 = 2 ( 4x + 1 )
42 = 8x + 2
8x = 42-2
8x = 40
x = 40/8
x = 5 m

P = ( 3x - 2 )
p = ( 3(5) - 2 )
p = 15 - 2
p = 13 cm

L = ( x + 3 )
l = 5 + 3
l = 8 cm

Luas = Panjang × Lebar
Luas = 13 × 8
Luas = 104 cm²