Hitunglah volume gas berikut pada STP 1. 3,4 gram gas amonia NH3 (Ar N=14 H=1) 2. 0,7 gram gas N2 (Ar N=14) 3. 4 gram gas SO2 (Ar S=32 O=16)

Stoikiometri
Kelas 10

cepet ajah yah
n = m/Mr
V saat STP = n x 22,4

1)
Mr = 14 + 3(1) = 17g/mol
n = 3,4/17 = 0,2 mol
V = 0,2 x 22,4 = 4,48 L

2)
Mr= 2 x 14 = 28 g/mol
n = 0,7/28 = 0,025 mol
V = 0,025 x 22,4 = 0,56 L

3)
Mr = 32 + 2(16) = 64
n = 4/64 = 0,125 mol
V = 0,125 x 22,4 = 2,8 L

dalam keaadan STP berlaku rumus mol=volume/22,4
1.mol=gr/mr=3.4/17=0.2
volume=mol*22.4=0.2*22.4
=4.48 liter

2.mol=0.7/28=0.025 mol
volume=0.025*22.4=0.56 liter

3.mol=4/64=0.0625
volume=0.0625*22.4=1.4 liter