Persamaan kuadrat 2x²-6+1=0 mempunyai akar akar x1 dan x2 nilai dari 2x1²+2x2²

x1 + x2 = -b/a = 3
x1x2 = c/a = 1/2
2x1^2 + 2x2^2 = 2(x1^2 + x2^2)
= 2((x1 + x2)^2 - 2x1x2)
= 2(3^2 - 2(1/2))
= 2(9 - 1)
= 16